34 people want to do this.

become so jaded and bitter that I drop out of society to live in the wilderness in a timber hut while tending to abstract mathematical theorems, the "MANIFESTO" and have conversations with the ghosts of dead 80's hair metal acts.


 

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Untitled 7 months ago

I’m so over it.



Untitled 14 months ago

ohh, so close but it slipped away, but I got a chance to talk to Eric Singer about joining Styx. Cool stuff, but god damn it, I didn’t think about how I would build a hut until I moved to Arizona. not many trees here… Ah ha! I shall use mud!!!



The Twelve Days of Christmas 23 months ago

The gifts add up

The popular Christmas carol starts innocuously enough. On day one, the character in the song gets a single present (a partridge in a pear tree). But on day two, the beneficiary receives a new present (a pair of turtle doves) plus another partridge in a pear tree. Day three brings a second helping of day two’s gifts, plus more new items (three French hens). By the twelfth day, the narrator is an undeniable pack rat – and maybe in violation of local zoning – after receiving 12 drummers drumming, and new copies of all the previous day’s gifts.

By the twelfth verse of the song, there are a lot of gifts. How do you count it all up? Pure arithmetic provides the easiest, though longest, way to do it:

The total, 364 gifts, means that our true love gets a present for almost every day of the year!

Greeks bearing gifts – triangular numbers
Here’s where some neat mathematical patterns come in, according to Bill Butterworth, professor of mathematics at Barat College of DePaul University in Illinois. The individual sums on each row-(1+2), (1+2+3) and so on-are what the ancient Greeks called “triangular numbers” because they make a triangle if you replace the numbers with X’s.

The triangular numbers form a sequence: 1, 3, 6, 10, and so on.

Instead of doing drawn-out arithmetic, you can simply use the triangular numbers to find out the number of gifts bestowed on any day of the song. For example, the 12th triangular number, 78, corresponds to the number of gifts granted in day 12. How many gifts were furnished on day 10? You just look up the 10th triangular number: 55.

Adding up the first 12 triangular numbers gives you the total number of gifts mentioned in the song: 364.

Pascal’s Triangle
The daily and 12-day totals for the gifts show up in another, more remarkable math pattern, discovered over a millennium ago and shaped coincidentally like a Christmas tree. It’s called Pascal’s Triangle, named after the Renaissance French mathematician Blaise Pascal, who developed it after its discovery by Arab, Chinese, and Persian mathematicians.

Today, Pascal’s Triangle has a wide range of uses in probability theory, fractals, calculus, and many other areas of math. “I’ve found Pascal’s Triangle to be one of the richest and most accessible mathematical ‘objects’ over the years,” says Butterworth. Indeed, Pascal’s triangle contains an astounding bag of mathematical tricks that includes more than one holiday connection.

The first fourteen rows of Pascal’s Triangle look like this:

To identify any number on the triangle, mathematicians specify its horizontal “row” and its diagonal “column,” with both column and row numbers starting at 0. For example, the third row is 1, 2, 1, and the first column (in either direction) is 1, 2, 3, 4, and so on.

How are the numbers chosen? In the triangle, every number, such as 10 (in row 6, column 3), is the sum of the two numbers in the previous row diagonally above it – 4 and 6:

This simple rule yields many powerful numerical patterns-including one that we’ve seen before.

“The triangular numbers – 1, 3, 6, 10, and so on – appear in the second column of Pascal’s triangle,” Butterworth points out. That’s the first ingredient for “The Twelve Days of Christmas” connection.

Twelve days in the triangle
The second ingredient is a math result known – coincidentally once again – as the Christmas Stocking Theorem.

The Christmas Stocking Theorem says this: Go to the top of any column, and select a diagonal string of as many numbers as you’d like down that column. To find the sum of those numbers, you don’t have to add them up. You can find the sum nearby in the triangle. Just put your finger on the last number in the string; move your finger to the next number in the column; then slide your finger over to the next column. That number provides the sum of the string.

To apply this to the “Twelve Days,” let’s choose column 2, the one with the triangular numbers. Then, choose the first 12 numbers.

According to the Christmas stocking theorem, you can find the sum of those numbers by putting your finger on the last number of the twelve-78-then going to the next number in the column – 91 – and then sliding over to the next column. What number do you find there? 364!

This same pattern works for any column of the triangle. As you may have noticed, there is actually a connection to Christmas stockings: When highlighted, the string of numbers down the column resembles the shank of a Christmas stocking hanging from the tree, while the sum appears in the toe! Because of this shape, the Christmas Stocking Theorem is also known as the “Hockey Stick Theorem,” another popular winter pastime.



Exactly HOW jaded and bitter 2 years ago

is jaded and bitter enough? I mean, how does one go about measuring this?

This goal is one of my more difficult ones… Ghosts of dead 80’s hair metal acts are extremely hard to come by. And I don’t care much for the Manifesto either.

Ah well, stick with the abstract math I guess.



Definately bitter and Jaded but not top flash on the rest yet. 2 years ago

Dead eighties hair metal muso’s definately not cos I thought Axl was dead but the fucker’s still rockin.

I have to learn a shit load more about maths but I’ll have plenty of time in the cabin. Also seen as how everything’s all been fuckin done before anyway maybe just rewrite Kurchinskies Manifesto and steal a bit from Marx and Nieztche. Then I’ll plea for money from my middle class former friends and talk to my horse.



Perhaps some Polynomials... 2 years ago

Let F be a set on which two binary operations are defined, called addition and multiplication, and denoted by + and · respectively. Then F is called a field with respect to these operations if the following properties hold:

(i) Closure: For all a,b F the sum a + b and the product a·b are uniquely defined and belong to F.

(ii) Associative laws: For all a,b,c F,
a+(b+c) = (a+b)+c and a·(b·c) = (a·b)·c.

(iii) Commutative laws: For all a,b F,
a+b = b+a and a·b = b·a.

(iv) Distributive laws: For all a,b,c F,
a·(b+c) = (a·b) + (a·c) and (a+b)·c = (a·c) + (b·c).

(v) Identity elements: The set F contains an additive identity element, denoted by 0, such that for all a F,
a+0 = a and 0+a = a.

The set F also contains a multiplicative identity element, denoted by 1 (and assumed to be different from 0) such that for all a F,
a·1 = a and 1·a = a.

(vi) Inverse elements: For each a F, the equations
a+x = 0 and x+a = 0

have a solution x F, called an additive inverse of a, and denoted by -a.
For each nonzero element a F, the equations

a·x = 1 and x·a = 1

have a solution x F, called a multiplicative inverse of a, and denoted by a-1.


Yeah, at least this shit makes sense. Verses real life…



All horses are the same color (Proof by induction) 2 years ago

Proof

It is obvious that one horse is the same color. Let us assume the proposition P(k) that k horses are the same color and use this to imply that k+1 horses are the same color. Given the set of k+1 horses, we remove one horse; then the remaining k horses are the same color, by hypothesis. We remove another horse and replace the first; the k horses, by hypothesis, are again the same color. We repeat this until by exhaustion the k+1 sets of k horses have been shown to be the same color. It follows that since every horse is the same color as every other horse, P(k) entails P(k+1). But since we have shown P(1) to be true, P is true for all succeeding values of k, that is, all horses are the same color.

And yet, it still makes more sense than any man I know!



I've always loved this one, Buffon's Needle problem!!! 2 years ago

Find the probability that a needle of length will land on a line, given a floor with equally spaced parallel lines a distance apart.

Yeah, I know, discrete math, not exactly abstract math, but still in the spirit of the goal.



Abstract math 3 years ago

Gotta love it! :)

Let’s see… Prime number theorem seems to be a good place to start. This should keep my mind occupied for awhile or put me to sleep. Either way, it’s a good thing.



I got the bitter and jaded part down 3 years ago

I need to develop a love of wilderness and timber huts… then I’m outta here.



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